Volume emptied in our experiment was 500 mL. we deviated from experiment instructions to ease calculations. Height of water in the bucket was kept the same at roughly 3 inches.
We made six runs for time needed to empty 500 mL, here are the data sets:
29.70s
29.21s
29.54s
29.56s
29.50s
29.20s
The theoretical time to empty 500 mL:
Volume emptied: 500 mL = 0.000500 m^3
Area of drain hole: pi*r^2 = 5.67*10^-5
Acceleration: 9.81 m/s
height of water: 3 inches = .8 m
t_theoretical = V/(A*sqrt(2gh))
Calculation & error analysis in MATLAB:
>> properror(t,[v a h],[.000500 5.67*10^-5 .8], [.000001 .01*10^-5 .1])
ans =
[ 26.7100] '+/-' [1.6709]
'Percent Error' '+/-' [6.2557]
t_theoretical vs t_actual:
| actual | theoretical | percent error |
| 29.7 | 26.71 | 11.19% |
| 29.21 | 26.71 | 9.36% |
| 29.54 | 26.71 | 10.60% |
| 29.56 | 26.71 | 10.67% |
| 29.5 | 26.71 | 10.45% |
| 29.2 | 26.71 | 9.32% |
Values do not agree within uncertainty (1.67, 6.25%)
solving for diameter:
2*r=V/(pi*t*sqrt(2*g*h))
r =
v/(2*pi*t*((981*h)/50)^(1/2))
>> properror(r,[v t h], [.000500 26.71 .8],[.000001 .01 .1])
ans =
[ 7.5201e-007] '+/-' [4.7025e-008]
'Percent Error' '+/-' [ 6.2533]
%error in the drill diameter = given-calculated/calculated
= 48.9% error


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